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x^2+1.80x-5.40=0
We add all the numbers together, and all the variables
x^2+1.80x-5.4=0
a = 1; b = 1.80; c = -5.4;
Δ = b2-4ac
Δ = 1.802-4·1·(-5.4)
Δ = 24.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.80)-\sqrt{24.84}}{2*1}=\frac{-1.8-\sqrt{24.84}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.80)+\sqrt{24.84}}{2*1}=\frac{-1.8+\sqrt{24.84}}{2} $
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